So the current is.

Any **resistor** in a circuit that has a voltage drop across it dissipates electrical power.

. This is of the form of the equation of a straight line y = m x + c.

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(c) 60 J.

2 joules/cal (1 joule = 107 ergs) = 1400 ft. . Sorted by: 2.

This energy goes into **heat**, much like the way a ball of putty that falls off a cliff converts its potential energy to **heat** when it hits the ground.

Viewed 990 times. Share. **Heat** produced across a **resistor** can be computed by the following formulae.

Y = 1 R + 1 j ω L = 1 R − j 1 ω L. P = I*V = I 2 R = V 2 /R, using our definition of resistance.

Remember that power is the rate at which energy is consumed.

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R= R = \Omega Ω. which claims that, to calculate the **heat** **dissipated** by the cable, we can use the Stefan-Boltzmann equation:.

The Joule effect describes the **heat dissipated** by a **resistor** when an electrical current ﬂows, with a corresponding power equal to the product of the current and voltage in the **resistor**, P=VI. .

mW is an abbreviation of Milli Watt.

Cite.

class=" fc-falcon">1. The total energy **dissipated** in the **resistor** over the first 3 milliseconds is approx. V = J C.

The four bands are used to identify the **resistor**. H=I²Rt. The symbol H H has been used to mean two different things. (unofficial) solutions document, which claims that, to calculate the **heat dissipated** by the cable, we can use the Stefan-Boltzmann **equation**. . H= (V²/R)t Going by #1, **heat** is directly proportional to the resistance.

I.

. As the current through a series increase, the total power **dissipated** in each component decreases.

I.

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Step 1/2.

A **resistor** has four colored bands, as shown in Figure \(\PageIndex{4}\).